1-10x+25x^2-144-66x-9x^2=0

Solution for 1-10x+25x^2-144-66x-9x^2=0 equation:

1-10x+25x^2-144-66x-9x^2=0

We add all the numbers together, and all the variables

16x^2-76x-143=0

a = 16; b = -76; c = -143;
Δ = b2-4ac
Δ = -762-4·16·(-143)
Δ = 14928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14928}=\sqrt{16*933}=\sqrt{16}*\sqrt{933}=4\sqrt{933}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-4\sqrt{933}}{2*16}=\frac{76-4\sqrt{933}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+4\sqrt{933}}{2*16}=\frac{76+4\sqrt{933}}{32}
$